4x^2+28x-68=0

Solution for 4x^2+28x-68=0 equation:

4x^2+28x-68=0

a = 4; b = 28; c = -68;
Δ = b2-4ac
Δ = 282-4·4·(-68)
Δ = 1872
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1872}=\sqrt{144*13}=\sqrt{144}*\sqrt{13}=12\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-12\sqrt{13}}{2*4}=\frac{-28-12\sqrt{13}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+12\sqrt{13}}{2*4}=\frac{-28+12\sqrt{13}}{8}
$